Given a
number n and two digits a and b. Replace every occurrence
of digit a in n with digit b.
Input. Three integers n (1 ≤ n
≤ 109), a, b (0 ≤ a, b ≤ 9).
Output. Print the resulting number after the
replacements. Leading zeros should not be included in the output.
Sample
input |
Sample
output |
123118 1 5 |
523558 |
SOLUTION
strings
Read the number n
as a string and the digits a and b as characters. Replace all
occurrences of character a in the string n with character b.
Then print the resulting string, removing any leading zeros. If the final
string consists only of zeros, print a single zero.
The resulting number may
exceed the range of the int type. For example, if n = 1000000000 (109), a = 1, b =
9, the result will be 9000000000 (9 * 109).
Algorithm implementation
Store the number n
as a string in the array s.
char s[100];
Read the number n
as a string and the digits a and b as characters.
scanf("%s
%c %c",s,&a,&b);
Replace all occurrences of character a with character b in
the string s.
for
(i = 0; i < strlen(s); i++)
if (s[i] ==
a) s[i] = b;
Convert the string s into a number res of type long long.
res = atoll(s);
Print the answer.
printf("%lld\n", res);
Algorithm implementation – string
Read the number n
as a string and the digits a and b as characters.
cin >> s >> a >> b;
Replace all occurrences of character a with character b in
the string s.
replace(s.begin(), s.end(), a, b);
Convert the string s into a number res of type long long.
res = stoll(s);
Print the answer.
cout << res << endl;
Java implementation
import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
String s = con.next();
char a = con.next().charAt(0);
char b = con.next().charAt(0);
s = s.replace(a,b);
int flag = 0;
for(int i = 0; i < s.length(); i++)
if (s.charAt(i) != '0')
{
s = s.substring(i);
flag = 1;
break;
}
if (flag == 0) s = "0";
System.out.println(s);
con.close();
}
}
Python implementation
Read the input data as
strings.
s, a, b = input().split()
Replace all occurrences of character
a with character b in the string s.
s = s.replace(a, b)
Convert the string s into an integer and print the result.
print(int(s))